QUESTION 1 If p=0.6 and q=0.4, calculate the expected frequency of the homozygou

Question

QUESTION 1 If p=0.6 and q=0.4, calculate the expected frequency of the homozygous dominant genotype if Hardy-Weinberg equilibrium conditions prevail 0.24 0.36 0.48 0.60 QUESTION 2 If p=0.6 and q=0.4, calculate the expected frequency of the homozygous recessive genotype if Hardy-Weinberg equilibrium conditions prevail 0.16 0.36 0.48 0.80 QUESTION 3 If p=0.6 and q=0.4, calculate the expected frequency of the heterozygous genotype if Hardy-Weinberg equilibrium conditions prevail 0.16 0.36 0.48 0.50

Explanation / Answer

Answer -1(b) p=0.6 so frequency of homozygous dominant = p2= 0.36

Answer -2(A) q= 0.4 so frequency of homozygous recessive will be q2 = 0.16

Answer -3(C) frequency of individual with heterozygous genotype will be 2 pq = 2× 0.6×0.4= 0.48

Answer -7 for evolution to occur it must that trait to be inherited .

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