The near point of a person\'s eye is 64.2 cm. To see objects clearly at a distan

Question

The near point of a person's eye is 64.2 cm. To see objects clearly at a distance of 23.0 cm, what should be the focal length and power of the appropriate corrective lens? (Neglect the distance from the lens to the eye.) focal length of the appropriate corrective lens power of the appropriate corrective lens The distance between the eyepiece and the objective lens in a certain compound microscope is 19.5 cm. The focal length of the eyepiece is 2.15 cm and that of the objective is 0.390 cm. What is the overall magnification of the microscope?

Explanation / Answer

object distance p = 23 cm

image distane q = -64.2

from lens equation

1/p + 1/q = 1/f

1/23 - 1/64.2 = 1/f

f = 35.8 cm <<<------answer

power P = 1/f(in metere) = 1/0.358 = +2.79 Diopters

++++++++++++++

magnification M = LD/(fo*fe)

M = (19.5*25)/(0.29*2.15)

M = 781.8

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