A radiation specialist prescribes a dose of 90.0 rem for a patient, using an app
ID: 1512187 • Letter: A
Question
A radiation specialist prescribes a dose of 90.0 rem for a patient, using an apparatus that emits alpha particles.
Part A
How many rads does this dose provide to the patient?
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Part B
How much energy does a 7.00 g sample of irradiated tissue receive?
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Part C
Suppose your hospital has only an electron source available. How many rads should you administer to this patient to achieve the same 90.0 rem dose?
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A radiation specialist prescribes a dose of 90.0 rem for a patient, using an apparatus that emits alpha particles.
Part A
How many rads does this dose provide to the patient?
D = radSubmitMy AnswersGive Up
Part B
How much energy does a 7.00 g sample of irradiated tissue receive?
E = JSubmitMy AnswersGive Up
Part C
Suppose your hospital has only an electron source available. How many rads should you administer to this patient to achieve the same 90.0 rem dose?
D = radSubmitMy AnswersGive Up
Explanation / Answer
Part A... A rad is a unit of absorbed dose. A rem is the unit of equivalent dose.
The relation between the two is as follows
equivalent dose = absorbed dose x w_R, where w_R is the radiation weighting factor which depends on the particule and it's energy.
w_R ranges from 1 for x-rays, gamma-rays up to 20 for alphas, heavy nuclei and MeV range neutrons
so , rem = D x w_R
or, D = rem / w_R = 90/20 = 4.5 rad
Part B... The absorbed dose is the energy deposited per kilogram, while the equivalent dose measures the biological damage done.
sample of irradiated tissue = 7.00 gram = 7 x 10^(-3) kg
so, D = energy / sample of irradiated tissue
or, energy = 4.5 rad x 7 x 10^(-3) kg = 0.0315 rad x kg
but 1 rad = 0.01 J/kg
so, energy = 0.0315 rad x kg x 0.01 J/kg = 3.15 x 10^(-4) joule
Part C....D = rem / w_R
here the value of w_R for elctron source is 2
so, D = 90/2 = 45 rad
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