Need all answers Fission is often achieved by bombarding a U-235 nucleus with a

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Fission is often achieved by bombarding a U-235 nucleus with a neutron, temporarily creating a highly unstable U-236 nucleus, which then can decay in a number of different ways. One such way is shown here (omitting the temporary U-236 nucleus). Fill in the missing product, including subscripts and superscripts, in the nuclear fission reaction shown here. Use the notation where X is the atomic symbol, Z is the atomic number, and A is the atomic mass number. N + u rightarrow + Sr + 2n How much energy is released during this reaction? The masses involved are as follows:| neutron: 1.008 665 u U-235: 235.043 923 u Sr-93: 92.914 026 u unknown daughter nucleus: 140.926 650 u

Explanation / Answer

(a)
The missing proudct is, 141Xe54

Where,
A = 141
Z = 54
X = Xe

(b)
Energy Released,
Mass of Reactants, = 1.008665 + 235.043923 = 236.052588 u
Mass of Products, = 140.926659 + 92.914026 + 2*(1.008665) = 235.858015 u

Energy Released = (236.052588 - 235.858015) * 931.5 Mev
Energy Released = 181.24 Mev

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