m RCES 034 OC M Wiley PLUS Solution Manual Wiley pd x Physics question I Chegg X
ID: 1511015 • Letter: M
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m RCES 034 OC M Wiley PLUS Solution Manual Wiley pd x Physics question I Chegg X C edugen.wileyplus.com/edugen/student/mainfr.uni EEE Apps HP Connected h NHL Live Strea Watch NBA Live strea Gradebook ORION y & Practice Assignment NEXT FULL SCREEN PRINTER VERSION BACK Chapter 08, Problem 091 Two blocks, of masses M 2.0 kg and 2M, are connected to a spring of spring constant k 190 N/m that has one end fixed, as shown in the figure. The horizontal surface and the pulley are friction and the pulley has negligible mass. The blocks are released from est with the spring relaxed. (a) what is the combined kinetic energy of the two blocks when the hanging block has fallen 064 0.088 m? b) What is the kinetic energy of the hanging block when it has fallen that 0.088 m? (c) What maximum distance does the hanging block fall before momentarily stopping? 029 035 057 019 00 019 053 2M Study (a) Number Units (b) Number Units (c) Number Units SHOW HINT GO TUTORIAL LINK TO TEXT LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE 11:34 PM I'm Cortana. Ask me anything. 4/27/2016Explanation / Answer
a) Apply conservation of energy
gain kinetic energy + elastic potentail energy = loss of graviatational potential energy
KE + 0.5*k*x^2 = 2*M*g*x
KE = 2*M*g*x - 0.5*k*x^2
= 2*2*9.8*0.088 - 0.5*190*0.088^2
= 2.714 J <<<<----------Answer
b) Kinetic energy of hnging block = (2/3)*2.714
= 1.809 J <<<<----------Answer
c) Apply conservation of energy
0.5*k*x^2 = 2*M*g*x
==> x = 4*M*g/k
= 4*2*9.8/190
= 0.4126 m <<<<----------Answer
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