About 1 of every 3300 water molecules contains one deuterium atom. If all the de

Question

About 1 of every 3300 water molecules contains one deuterium atom. If all the deuterium nuclei in 13 L of water are fused in pairs according to the D-D fusion raction (below), how much energy is liberated?^2H +^2H rightarrow^3He + n + 3.27 Mev___________J Burning liquid ethance produces about 2.70 times 10^7 J/L. Calculate the energy liberated from the burning of 13 L of liquid ethande.______________J Compare this answer with the energy obtainable from the fusion of the deuterium in 13 L water. E_liquid ethane/E_fusion =______________Need Help?

Explanation / Answer

3 L of water mass = 3000 gms

molecular weight of water = 18 gms

no. of water molecules in the sample = (3000/18 )*6.02e+23

number of water molecule having deutrium = (3000/18)*6.02e+23* (1/3300)

                                                                                = 0.31e+23

each water molecule contains 2 deuterium molecules.

number of fusions = 0.3e+23

energy = 0.31e+23 *3.27 Mev

               = 0.31e+23*3.27*1.6e-13 J

              = 1.62e+10 J

burning ethane

energy = 13*2.7e+7   = 35.1e+7 J

Eli-eth /Efu   = 35.1e+7 / 1.62e+10 = 21.67e-3

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