The proton-proton cycle consists of the following fusion reactions: 1H + 1H 2H +
ID: 1509956 • Letter: T
Question
The proton-proton cycle consists of the following fusion reactions: 1H + 1H 2H + e+ + nu bare 1H + 2H 3He + 3He + 3He 4He + 1H + 1H (a) Calculate the energy released by the reaction burning 1H to produce 2H . (Note: the mass energy of the positron is released, because it quickly annihilates with an electron.) .42 Incorrect: Your answer is incorrect. MeV (b) Calculate the energy released by the reaction burning 1H and 2H to produce 3He . MeV (c) Calculate the energy released by the reaction burning 3He to produce 4He and more 1H . MeV (d) What is the total energy released by the cycle? MeV
Explanation / Answer
A) energy released= 2*Ehydrogen+Eelectron-2*Hydrogen = Eelectron= 0.511MeV
B)energy released=3*(Ehelium-Ehydrogen)
=3*(4.001506*931.3-938.790)=8363.4365MeV
C)energy released=4*Ehelium+2*Ehydrogen-6*Ehelium =2*Ehydrogen-2*Ehelium=2*938.79-2*4.001506*931.3=5574.625MeV
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.