Using the picture of the signal of voltage versus time from the screen of the os

Question

Using the picture of the signal of voltage versus time from the screen of the oscilloscope and assuming that the settings on the oscilloscope are 2V/div and 2ms/div, calculate the following Using the picture of the signal of voltage versus time from the screen of the oscilloscope and assuming that the settings on the oscilloscope are 2V/div and 2ms/div, calculate the following: 1. A. Amplitude (express as a whole number 00Hz B. Period (in miliseconds) 3V C. Frequency (round to the tens place) Vrms value (express as a whole number) 6V Vpp (peak to peak) value (express as a10 2V D. E. whole number)

Explanation / Answer

a) i subdivision = 0.4 volt = 0.4 ms

amplitude = from zero to max = 1 complete division + 3 subdivision = 2 + 3*0.4 = 2 + 1.2 = 3.2 V

amplitude = 3 V whole number

b)

period (time difference between three consicutive zeros) = 5 complete division = 5 * 2 ms = 10ms

c)

frequency = 1/T = (10*10^(-3))^(-1) = 100 Hz

d)

vrms = Vpeak / sqrt(2) = 3.2 / sqrt(2) = 2.26 V = 2 V(whole number)

e)

Vp-p = distance between maxima to minima = 15 subdivision = 15 * 0.4 v = 6 V

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