In searching the bottom of a pool at night, a watchman shines a narrow beam of l
ID: 1508552 • Letter: I
Question
In searching the bottom of a pool at night, a watchman shines a narrow beam of light from his flashlight, 1.3mabove the water level, onto the surface of the water at a point d = 2.5 m from his foot at the edge of the pool(Figure 1) .
Part A
Where does the spot of light hit the bottom of the h = 2.1-m-deep pool? Measure from the bottom of the wall beneath his foot.
Express your answer to two significant figures and include the appropriate units.
A certain lens focuses light from an object1.75 m away as an image 41.8 cm on the other side of the lens.
Part A
What type of lens is it?
What type of lens is it?
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Part B
What is its focal length? Follow the sign conventions.
Express your answer to three significant figures and include the appropriate units.
0.62cm
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Incorrect; Try Again; 4 attempts remaining
Part C
Is the image real or virtual?
Is the image real or virtual?
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converging divergingExplanation / Answer
PART A)
We find the angle of incidence from the distances tan 1 = d1 /h1 = 2.5m /1.3m = 1.9231, 1 = 62.53 .
For the refraction from air into water:
we have nair sin 1 = nwater sin 2,
sin 2 = 1.00/ 1.33 sin 62.53 2 = 41.84 We find the horizontal distance from the edge of the pool from l = d1 + d2 = d1 + h2 tan 2 = 2.5m + 2.1m tan 41.84 = 4.4m
Focal length , f = Oi/O+i = 1.75*(-0.418)/1.75-0.418 = - 0.549 m = Negative f
=> Concave lens
=> Diverging lens
PART B)
f = - 0.549 m
PART C)
Image is Real & Inverted
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