(a) What is the maximum value of the current in the circuit? 0.0795 A (b) What a

Question

(a) What is the maximum value of the current in the circuit?
0.0795 A

   

(b) What are the maximum values of the potential difference across the resistor and the capacitor?
VR,max = 151 V

   
VC,max = 84.3 V

   

(c) When the current is zero, what are the magnitudes of the potential difference across the resistor, the capacitor, and the AC source?
VR = 0 V

   
VC = 84.3 V

Vsource = 84.3 V
How much charge is on the capacitor at this instant?
qc = 211µC

   

(d) When the current is at a maximum, what are the magnitudes of the potential differences across the resistor, the capacitor, and the AC source?
VR = 151 V

   
VC = 0 V

   
Vsource = 151 V

   
How much charge is on the capacitor at this instant?
qc = 0 µC

    Can you please show solution to solve. I provided the correct answers Thak You!

Explanation / Answer

ANSWER

a)

Capacitive reactance

Xc=1/2pifC =1/2pi*60*(2.5*10-6) =1061.03 ohms

Impedance

Z=sqrt[R2+Xc2]=sqrt[19002+1061.032]=2176.19 ohms

maximum current

Imax=Vmax/Z =173/1678.03

Imax= 0.0795 A

b)

VR,max=Imax*R =0.0795*1900 =151.05 Volts

Vc,max=Imax*Xc=0.0795*1061.03 =84.35 Volts

c)

When Current is zero ,the instantaneous voltage across resistor is

VR=I*R=0 Volts

Instantaneous Voltage across capacitor is

Vc=Vmax =84.35 Volts

Instantaneous voltage around the circuit is

Vsource=VR+Vc=84.35 Volts

charge on the capacitor at that instant

Q=CV =(2.5)*84.35=210.87 uC = 211 uC

d)

When the current is at a maximum ,the instantaneous voltage across resistor is

VR=I*R=151.05 Volts

Instantaneous Voltage across capacitor is

Vc=0 Volts

Instantaneous voltage around the circuit is

Vsource=VR+Vc=151.05 Volts

charge on the capacitor at that instant

Q=CV =0 uC

Regards!!!

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