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Problem 23.58 A diverging lens with f = -34.5 cm is placed 13.0 cmbehind a conve

ID: 1507125 • Letter: P

Question

Problem 23.58

A diverging lens with f = -34.5 cm is placed 13.0 cmbehind a converging lens with f = 21.0 cm .

Part A

Where will an object at infinity be focused? Determine the image distance from the second lens. Follow the sign conventions.

Express your answer to two significant figures and include the appropriate units.

Problem 23.58

A diverging lens with f = -34.5 cm is placed 13.0 cmbehind a converging lens with f = 21.0 cm .

Part A

Where will an object at infinity be focused? Determine the image distance from the second lens. Follow the sign conventions.

Express your answer to two significant figures and include the appropriate units.

di2 =

Explanation / Answer

The image of the converging lens will be the object of the diverging lens

so 1/f = 1/do + 1/di since do = infinity di = f = 21 cm

this is 13 - 21 = - 8.0 cm for the image distance of the diverging lens

therefore 1/f = 1/do + 1/di

or 1/di = 1/f - 1/do

so di = f*do/(do - f) = -34.5*(- 8.0)/(-8.0 - (-34.5)) = 10.41 cm (behind the diverging lens)

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