Assume all temperatures to be exact. In an experiment, a 0.210-kg piece of a cer

Question

Assume all temperatures to be exact. In an experiment, a 0.210-kg piece of a ceramic material at 23 C is placed in liquid nitrogen at its boiling point to cool in a perfectly insulated flask, which allows the gaseous N2 to immediately escape. Part A How many liters of liquid nitrogen will be boiled away during this operation? (Take the specific heat of the ceramic material to be that of glass and the density of liquid nitrogen to be 0.80 × 103 kg/m3.) Express your answer using two significant figures.

Explanation / Answer

mass of glass: m = 0.21 kg
specific heat of glass: C = 0.84 kJ/kg-°K
glass temperature: T = 23 °C
mass of nitrogen: m' = V, .., where, V = volume.
boiling point of nitrogen: T' = -195.7 °C
density of nitrogen: = 0.8x10³ kg/m³
latent heat of vaporization of nitrogen: 201 kJ/kg

Q = mCT = 0.21*0.84*[23 -(-195.7)] = 38.57 kJ

This amount of heat is available to vaporize the nitrogen: Q = m'L = VL = 0.8x10³ V*201

38.57 = 0.8x10³ V*201

V = 0.0002398 m³ = 0.2398 L...........Ans.

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