A student stands d_0 = 2.7 m in front of a floor-to-ceiling mirror. Her eyes arc

Question

A student stands d_0 = 2.7 m in front of a floor-to-ceiling mirror. Her eyes arc h_c = 1.41 m above the floor and she holds a flashlight at a distance h_c = 0.55 m above the floor. Randomized Variables d_0 = 2.7m h_c = 1.41m h_f = 0.55m Calculate the angle theta, in degrees, that the flashlight makes with respect to the floor if the light is reflected into her eyes. Theta = Draw the optical path of a ray emitted by the flashlight and reflected into the student's eyes by the mirror, making sure that the ray obeys the law of reflection. Look for a right triangle, one of whose angles is the requested angle.

Explanation / Answer

Distance btw student & mirror, = 2.7 m
Distance between eyes anf flash light = 1.41 - 0.55 m = 0.86 m

Now,
tan() = (0.86/2)/2.7
= tan^-1((0.86/2)/2.7)
= 9.05o
Angle that Flash light makes with the floor, = 9.05o

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