Two light sources can be adjusted to emit monochromatic light of any visible wav

Question

Two light sources can be adjusted to emit monochromatic light of any visible wavelength. The two sources are coherent, 3.55 pm apart, and in line with an observer, so that one source is 3.55 pm farther from the observer than the other. (a)For what visible wavelengths (400 to 700 nm) will the observer see the brightest light, owing to constructive interference? (Enter your answers from smallest to largest starting with the first answer blank. Enter NONE in any remaining answer blanks.) (b)How would your answers to part (a) be affected if the two sources were not in line with the observer, but were still arranged so that one source is 3.55 |jm farther away from the observer than the other? (c) For what visible wavelengths will there be destructive interference at the location of the observer? (Enter your answers from smallest to largest starting with the first answer blank. Enter NONE in any remaining answer blanks.)

Explanation / Answer

for constructive interference

d= m*lambda

m = 0 , 1 , 2 , 3 , 4 ...

d = 3.55 um = 3.55 x 10^-6 m

lambda = d/m

m = 6

lambda = 5.9167 x 10^-7 m = 591.67 nm

m = 7

lambda = 5.0714 x 10^-7 m = 507.14 nm

m = 8

lambda = 4.4375 x 10^-7 m = 443.75 nm

m = 9

lambda = 0

part c )

for destructive interference

d = (m+1/2)*lambda

lambda = 2d/(2m+1)

m = 0 , 1, 2 ,3 ,4 ,,,,

m =5

lambda =2d/11

lambda = 645.45 nm

m = 6

lambda = 546.15 nm

m =7

lambda = 473.33 nm

m = 8

lambda = 417.65 nm

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