Two masses (m A = 3 kg, m B = 6 kg) are attached to a (massless) meter stick, at

Question

Two masses (mA= 3 kg, mB= 6 kg) are attached to a (massless) meter stick, at the 0 and 75 cm marks, respectively.

"A Physics 210-HW#9-Sp. x ( e Home | Chegg.com -> Dwww.webassign.net/web/Student/Assignment-Responses/submit?dep-13701 713 9. + -14.25 points My Notes Ask Your Teacher Two masses (mA= 3 kg, mB= 6 kg) are attached to a (massless) meter stick, at the 0 and 75 cm marks, respectively. a.) Where is the center of mass of this system? cm, from mass A b.) The system is then hung from a string, so that it stays horizontal. Where should the string be placed? cm, from mass A c.) Now, if mass B was removed, how much force would need to be exerted at the 100 cm mark in order to keep the meter stick level size N, dir: | Select-' d.) Now, if mass B was rempwan rad/s -Select- ards downwards ditional forc lied, calculate the size of the angular acceleration of the meter stick at that instant* For parts c-d, assume the string remains attached at the same location you found in part b Submit AnswerSave Pro Submit Assignment Save Assignment Progress Home My Assignments WebAssign® 4.0 1997-2016 Advanced Instructional Systems, Inc. All rights reserved. 8:32 AM

Explanation / Answer

a) center of mass is Xcm = ((m1*x1)+(m2*x2))/(m1+m2)

Xcm = ((3*0)+(6*0.75))/(3+6)

Xcm = 0.5 m = 50 cm from mass A

b) it should be hung at the center of mass

50 cm from mass A

C) to keep the stick level after removal of mass B we need to apply (3*9.8) N force = 29.4 N force

Upwards

D) Some text is covered ,not able to see the question 4)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.