Assume the wire visible in the plane is bent perpendicularly at A and at C, with

Question

Assume the wire visible in the plane is bent perpendicularly at A and at C, with the remainder of the wire behind the paper. A current of 2 A flows toward you at A, through the visible portion, and back in the opposite direction at C. Consider the wires below the plane at A and C to be semi-infinite. There is a magnetic field of strength 8.63 T into the paper (not including the field due to the current in the wire). What is the magnitude of the magnetic field at the center of the are O due to the current in the wire? Answer in units of T.

Explanation / Answer

magnetic field due to current in vertical and horizantal parts at point O is = 0

magnetic field due to circular part Bc = uo*I*theta/(4*pi*r)

theta = pi/2

Bc = (4*pi*10^-7*2)/(8*6)

Bc = 5.23*10^-8 T in to the page

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