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The figure below shows a long straight wire with current I to the right and thre

ID: 1504207 • Letter: T

Question

The figure below shows a long straight wire with current I to the right and three wire loops, all with the same clockwise current I around then. The loops are all the same distance from the long wire and have edge lengths of either L or 2 L. Rank the loops according to the magnitude ot the net force on them due to the current in the long straight wire, greatest first. iii ii I ii iii I iii i ii i ii iii I iii ii In the formula F^rightarrow = qv^rightarrow times B^rightarrow: F^rightarrow UpTee V^rightarrow but not necessarily F^rightarrow UpTee B^rightarrow F^rightarrow UpTee B^rightarrow but not necessarily to F^rightarrow UpTee v^rightarrow v^rightarrow UpTee B^rightarrow but not necessarily v^rightarrow UpTee F^rightarrow all three vectors must be mutually perpendicular none of the above A proton (charge e). traveling perpendicular to a magnetic held, experiences the same force as an alpha particle (charge 2e) which is also traveling perpendicular to the same field. The alpha particle has 4x the mass of the proton. The ratio of their speeds, v_proton/v_alpha is: 0.5 1 2 4 8

Explanation / Answer

(10)

F must be perpendicular to both v and B

option (E) is correct answer

(11)

For proton, Fp = evpB

For alpha particle, F =2evaB

The two forces are equal, then

evpB = 2evaB

vp = 2va, so the ratio is 2.

option(c) is correct answer

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