The figure below shows a long straight wire with current I to the right and thre
ID: 1504207 • Letter: T
Question
The figure below shows a long straight wire with current I to the right and three wire loops, all with the same clockwise current I around then. The loops are all the same distance from the long wire and have edge lengths of either L or 2 L. Rank the loops according to the magnitude ot the net force on them due to the current in the long straight wire, greatest first. iii ii I ii iii I iii i ii i ii iii I iii ii In the formula F^rightarrow = qv^rightarrow times B^rightarrow: F^rightarrow UpTee V^rightarrow but not necessarily F^rightarrow UpTee B^rightarrow F^rightarrow UpTee B^rightarrow but not necessarily to F^rightarrow UpTee v^rightarrow v^rightarrow UpTee B^rightarrow but not necessarily v^rightarrow UpTee F^rightarrow all three vectors must be mutually perpendicular none of the above A proton (charge e). traveling perpendicular to a magnetic held, experiences the same force as an alpha particle (charge 2e) which is also traveling perpendicular to the same field. The alpha particle has 4x the mass of the proton. The ratio of their speeds, v_proton/v_alpha is: 0.5 1 2 4 8Explanation / Answer
(10)
F must be perpendicular to both v and B
option (E) is correct answer
(11)
For proton, Fp = evpB
For alpha particle, F =2evaB
The two forces are equal, then
evpB = 2evaB
vp = 2va, so the ratio is 2.
option(c) is correct answer
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.