This question has several parts that must be completed sequentially. If you skip

Question

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise The position of a particle is given by the expression x = 7.00 cos (3.00nt + 2m/5), where x is in meters and t is in seconds. (a) Determine the frequency. (b) Determine period of the motion. (c) Determine the amplitude of the motion (d) Determine the phase constant. (e) Determine the position of the particle at t = 0.280 s. Part 1 of 4- Conceptualize The given expression describes the vibration by giving the position as a function of time. The frequency, period, amplitude, and phase constant completely describe the motion and we can determine their values from the function x(t) from the function x(T)

Explanation / Answer

x = 7 cos(3pi t + 2pi/5)

a) w = 2pif = 3pi

f = 1.5 Hz

b) T = 1/f = 1/1.5 = 0.67 sec

c) A = 7 m

d) phi = 2 pi/5 rad = 1.26 rad

e) at t = 0.280 sec

x = 7 cos[ (3 x pi x 0.280) + (2 x pi /5)

x = 7 cos(1.24pi) = 7 x cos(223.2 deg) = - 5.10 m

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