Problem 28.52 A 60-kg person receives a 250-mrad whole-body absorbed dose of rad

Question

Problem 28.52

A 60-kg person receives a 250-mrad whole-body absorbed dose of radiation.

Part A

How much energy does the person absorb? Use that 1rad=102J/kg.

Express your answer to two significant figures and include the appropriate units.

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Part B

Is it better to absorb 250 mrad of X-rays or 250 mrad of beta rays?

Is it better to absorb 250 mrad of X-rays or 250 mrad of beta rays?

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Part C

What is the dose in case of X-rays?

Express your answer to two significant figures and include the appropriate units.

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Part D

What is the maximum dose in case of beta rays? The maximum of RBE for beta rays is 1.7.

Express your answer to two significant figures and include the appropriate units.

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Explanation / Answer

ANSWER

Part A)

The amount of energy deposited from 1 kg of absorbing material = 10^-2 J

Mass of absorbing material = 60 kg

The energy deposited =60x10^-2 J

So, the energy is absorbed by a 60-kg person receiving a 250-mrad whole-body absorbed dose of radiation

            = (60x10^-2 J)(250x10^-3 rad)

              =  0.15 J   ANS.

Part B)

X-rays are much more penetrating than Beta-rays and hence more harmful for human body. Thus, it is better to absorb 250mrad of Beta-rays.

Part C)

The dose for x-rays is,

Dose in rem = Dose in rad X RBE

Dose in rem = (250 x 10^-3 rad)(1.0) = 0.250 rem   ANS.

Part D)

For beta rays,

Dose in rem = Dose in rad X RBE = (0.250 rad)(1.7) = 0.425 rem   ANS.

Regards!!!

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