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roblem 1. Using Coulomb\'s Law, find the force exerted on charge labeled \"q\" b

ID: 1502503 • Letter: R

Question

roblem 1. Using Coulomb's Law, find the force exerted on charge labeled "q" by the other harge for cases A, B, C, D, E, and F and then rank those forces according to their magnitude as directed below. CAREFULLY EXPLAIN YOUR REASONING In each case shown below, small charged particles are fixed on grids having the same spacing. Eac charge q is identical, and all the other charges have a magnitude that is an integer multiple of q. +24 +16q Rank the magnitude of the electric force on the charge labeled g due to the other charge. Greatest 1 2 OR, the electric force on q is the same but not zero for all six cases. OR, the electric force on q is zero for all six cases. OR, the ranking for the electric force on q cannot be determined"-- Carefully explain your reasoning.

Explanation / Answer

1)   Force on charge case A = k* q * 4q/4L2   =    k* q * q/L2

        Force on charge case B = k* q * 8q/16L2   =    k* q * q/2L2

      Force on charge case C = k* q * 2q/2L2   =    k* q * q/L2

       Force on charge case D = k* q * 8q/8L2   =    k* q * q/L2

        Force on charge case E = k* q * 16q/16L2   =    k* q * q/L2

      Force on charge case F = k* q * 4q/5L2   =    0.8 * k* q * q/L2

=>   Ranking of Force =>     A = C = D = E > F > B

2)     Hair dryer    -   power = VI = 120 * 12 = 1440 W

        Energy    consumed   =   4.32 kWh

=> Cost =   0.12 * 4.32 = $ 0.5184

Cofee maker    -   power = VI = 120 * 9 = 1080 W

        Energy    consumed   =   3.24 kWh

=> Cost =   0.12 * 3.24 = $ 0.3888

Light Bulb -   power = VI = 100 W

        Energy    consumed   =   24 kWh

=> Cost =   0.12 * 24 = $ 2.88

Led Light Bulb -   power = VI = 5 W

        Energy    consumed   =   1.2 kWh

=> Cost =   0.12 * 1.2 = $ 0.144

Attic Fan -   power = VI = 140 W

        Energy    consumed   =   42 kWh

=> Cost =   0.12 * 42 = $ 5.04

Microwave oven -   power = VI = 120 * 8.3 = 996 W

        Energy    consumed   = 7.47 kWh

=> Cost =   0.12 * 7.47 = $ 0.8964

3)   Here, Req = 40 ohm

=> Itot = 60/40   = 1.5 A

=>   I1 = I2 = I3 = 1.5 A

=> V1 = 25.5 V

=> V2 =   18 V

=> V3   =   16.5 V

4)   Req = 3.523 ohm

=> Itot = 12/3.523   = 3.406 A

=> V1 = V2 = V3 = 12 V

=> I1 = 12/11 = 1.09 A

=> I2 = 12/7 = 1.714 A

=> I3 = 12/20   = 0.6 A