(a) What is the force (magnitude and direction) on the electron when it is betwe

Question

(a) What is the force (magnitude and direction) on the electron when it is between the plates?
Magnitude
.................................................. N

(b) What is the acceleration of the electron (magnitude and direction) when acted on by the force in part (a)? (Ignore gravitational effects.)

Magnitude
........................................ m/s2

(c) How far below the axis has the electron moved when it reaches the end of the plates?
....................................... mm
(d) At what angle with the axis is it moving as it leaves the plates?
................................................. °
(e) How far below the axis will it strike the fluorescent screen S?
..................................................cm

Explanation / Answer

a)
Force will be in downward direction
F = q*E
= (-1.6*10^-19)*(1.26*10^3)
= -2.016*10^-16 N
Magnitude= 2.016*10^-16 N

b)
Direction downward

Magnitude= F/m
= (2.016*10^-16)/(9.11*10^-31)
=2.213*10^14 m/s^2

c)
time taken to move end of plate = 16 cm/v
= 0.16 m / (5.40*10^6)
=2.963*10^-8 s

distance moved below the axis be y
y = 0.5*a*t^2
= 0.5*(2.213*10^14) * (2.963*10^-8)^2
=0.097 m
= 07 mm

d)
vy = a*t
= (2.213*10^14) * (2.963*10^-8)
= 6.56*10^6 m/s

vx = 5.4*10^6 m/s

angle below axis = atan (vy/vx)
= atan (6.56*10^6 / 5.4*10^6)
= 50.5 degree

I am allowed to answer only 4 parts at a time

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