M I F s Mastering Physics: Homework 11 Google Chrome https:// session. mastering

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M I F s Mastering Physics: Homework 11 Google Chrome https:// session. masteringphysics.com next&assignment; ProblemID-59361545 PHY122 Physics for the Life Sciences ll Spring 2016 signed in as Mark Szkolnicki l Helg Cose f d, Homework 11 Problem 18.38 1 1 Resources previous 8 of 18 next Part A 25 19 Problem 18.38 Calculate the image position. 0.01263 Express your answer to two significant figures and include the appropriate units A 2.0-cm-tall object is 15 cm in front of a concave mirror that has a 25 cm focal length. -0.01263 79.16 cm. The negative v s' Value Units im age 15 a virtu Submit My Answers Give Up from the defini incorrect; Try Again; 8 attempts remaining Part B Calculate the image height. Type a positive value if the image is upright and a negative value if it is inverted. Express your answer to two significant figures and include the appropriate units 79.16 cm 9 cm HA 16.66 cm alue Units View comments Submit My Answers Give Up Provide Feedback Continue I'm Cortana. Ask me anything 3:43 PM 4/19/2016

Explanation / Answer

Using Lenz' equation:

1/p + 1/q = 1/f

p=object distance = +15 cm
q=image distance
f=focal length = + 25 cm

1/15 + 1/q = 1/25

1/q = 1/25-1/15 = (15-25)/25*15

=-10/25*15 = - 2/75

q=-75/2 = --37.5cm (the sign convention for converging lenses is that -ve image distances are infront the lens; )


and the height of the image:

h = m*y where m = -s'/s

so h = 2.0*37.5/15 = 5 cm.

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