Part A Calculate the magnitude of the maximum orbital angular momentum L max for

Question

Part A

Calculate the magnitude of the maximum orbital angular momentum Lmax for an electron in a hydrogen atom for states with a principal quantum number of 3.

Express your answer in units of to three significant figures.

Part B

Calculate the magnitude of the maximum orbital angular momentum Lmax for an electron in a hydrogen atom for states with a principal quantum number of 41.

Express your answer in units of to three significant figures.

Part C

Calculate the magnitude of the maximum orbital angular momentum Lmax for an electron in a hydrogen atom for states with a principal quantum number of 186.

Express your answer in units of to three significant figures.

Explanation / Answer

The orbital angular momentum of an electron with principal quantum number n is:

L = nh/(2)

h = 6.626×10³ Js Planck constant

(a) L = 3*6 6.626×10³ Js/(2) = 18.921×1034 Js

(b) L = 41 6.626×10³Js/(2) = 43.089*10^-34 Js

(c) L = 186 6.626×10³ Js/(2) = 195.4 ×1034 Js

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