aspx PM Thermal conductivity k mework 14 Begin Date: 4/4/2016 12:00:00 AM Due Da

Question

aspx PM Thermal conductivity k mework 14 Begin Date: 4/4/2016 12:00:00 AM Due Date: 4/18/2016 11:00:00 PM End Date: 5/2/2016 11:00:00 (10%) Problem 6a Suppose a person is covered head to foot by wool clothing with an average thickness of d = 1.9 cm and is transferring energy by conduction through the clothing at the rate of Q/ -45 W. 1 Substance Wool Glass Human body Ceramic Wood Air Fatty tissue Styrofoam 0.84 0.010 Ctheespertta.com 50% Part (a) what is the temperature difference, in terms of the quantities given in the problem statement, across the clothing? Denote the surface area of the wool by A and the thermal conductivity by k Grade Summary Potential 100% Aempts semaining 1 4 5 6 123 detailed view Submit Hint Hinte-dedaim hint. Hines remaining: Ferdhack: deduction per feedback 50% Part (b) what is the temperature difference, in degrees Celsius, across the clothing, given ure difference, in degrees Celsius, across the clothing. given the surface area is 1.6 m2

Explanation / Answer

Here ,

d = 1.9 cm = 0.019 m

Q/dt = 45 W

part a) let the temperature difference is del T

as Q/dt = k * A * del T/d

del T = (Q/dt) * d/(k * A)

the temperatre difference is (Q/dt) * d/(k * A)

part b)

for the temperature difference

temperature difference = (45) * 0.019/( 0.04 * 1.6)

temperature difference = 13.4 degree C

the temperature difference is 13.4 degree C

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