During an X-ray examination a person receives a dose of 90 mrem in 3.6 kg of tis

Question

During an X-ray examination a person receives a dose of 90 mrem in 3.6 kg of tissue. The RBE of X-rays is 1.0. Use that 1 rad= 10-2 J/kg and 1 eV = 1.602×10-19 J.

Part A

Determine the total energy absorbed by the 3.6 kg of body tissue. Express your answer to two significant figures and include the appropriate units.

Part B

Determine the energy in joules of each 60,000-eV X-ray photon. Express your answer using two significant figures.

Part C

Determine the number of photons absorbed by that tissue. Express your answer using two significant figures.

Explanation / Answer

given,

radiation = 90 mrem or 0.09 rad

mass = 3.6 kg

1 rad = 10^-2 K / kg

so

0.09 rad = 0.09 * 10^-2 J / kg

total energy absorbed by the 3.6 kg of body tissue = 0.09 * 10^-2 * 3.6

total energy absorbed by the 3.6 kg of body tissue = 0.00324 J

1 eV = 1.602677·10-19 J

so,

60000 eV = 60000 * 1.602677·10-19 J

energy in joules of each 60000-eV X-ray photon = 9.616062 * 10^-15 J

number of photons absorbed by that tissue = 0.00324 / (9.616062 * 10^-15)

number of photons absorbed by that tissue = 3.37 * 10^11

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