Due this Friday, Apr 22 at 11:59 pm (EDT) You are shining ultraviolet light on a

Question

Due this Friday, Apr 22 at 11:59 pm (EDT)

You are shining ultraviolet light on a gas of an unknown element. You know that an electron starts in a ground state with an energy of -15.70 eV. The electron absorbs a 4.00-eV photon. The electron immediately drops to an intermediate energy state Einter of energy -14.10 eV (in this case we will assume it emits a photon when it drops to the intermediate state, though most often the energy is lost through other means). The electron promptly drops back down to the ground state.
What is the energy of the state which the electron is in after absorbing the UV photon?
-11.700 eV

You are correct.
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What is the energy of the first photon emitted?
2.400 eV

You are correct.
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What is the energy of the second photon emitted and is this process considered fluorescence or phosphorescence? (Both answers must be correct for the answer to be correct.)

fluorescence
phosphorescence

Explanation / Answer

the energy of the second photon emitted and is,

=15.70 eV--14.10 eV

=1.6 eV

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