An upright object with a height of 20 cm is placed 40 cm to the left of a. diver

Question

An upright object with a height of 20 cm is placed 40 cm to the left of a. diverging lens with a focal length of -25 cm. A concave spherical mirror with a focal length 15 cm is placed 30 cm to the right of the lens. Determine the following regarding the final image.

Type of image (Real or Virtual) ______________________

Location of the final image relative to the mirror _________________

Height of the image ____________________

Upright or Inverted ________________________

Magnification relative to the original object ______________________

Explanation / Answer

Apply thin lens formula,

1/f= 1/u +1/v ;

for diverging lens; {u=40; f=-25}

-1/25 = 1/v + 1/40 ; v=-15.38 cm {image is formed to the left of the lens}

Apply thin lens formula for mirror; here u=15.38 +30

1/15= 1/v+ 1/45.38 ;

v= 22.41 cm {to the right of the mirror}

image is real{since v>0}

image is located 22.41 cm to the right of the mirror

image is inverted {object deistance to mirror > f of the mirror}

magnification(M)= magnification from lens(m1)*magnification form the mirror(m2)

Since m=v/u; m1= 15.38/40 ; m2= 22.41/ (15.38 +30 )

M=0.19

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