will rate A 1 cm tall object is placed 5 cm to the left of a converging lens. Th

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A 1 cm tall object is placed 5 cm to the left of a converging lens. The focal length of this lens is 10 cm. Another converging lens of focal length 20 cm is place 15 cm to the right of the lens. What is the tall of the final image 4 cm 8 cm 10 cm 20 cm If we want to obtain a double slits interference pattern. What light source do we use? Use two beams from two different incandescent light bulb and shine on each slit. Use two beams from two different laser source and shine on each slit. Use two split beams from one incandescent light bulb and shine on each slit. Use two split beams from one laser source and shine on each slit.

Explanation / Answer

9) for first convering lens

f1 = 10 cm

do = 5 cm

then usong 1/f1 = (1/do)+(1/di)

1/10 = (1/5) +(1/di)

di = -10 cm

image due to 1st converging lens is virtual

magnification m1 = -di/do = hi/ho

hi = (10/5)*1 = 2 cm upright image

for the second converiging lense

object distance is do' = 25 cm

f2 = 20 cm

then using 1/f2 = (1/do) + (1/di)

1/20 = (1/25) + (1/di)

di = 100 cm to the right of the second lens

magnification m2 = hi/ho = -di/do

hi = (-100/25)*2 = -8 cm

8 cm inverted image

So the answer is 8 cm

10) to form the interfrence the Source must be a coherent

LASER is a coherent Source

So the correct answer is Use two split beams from one laser Source and shine on each slit

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