1. [2pt] What is the strength of the electric field between two plates separated
ID: 1499383 • Letter: 1
Question
1. [2pt]
What is the strength of the electric field between two plates separated by a distance 6.0 cm if there is a potential difference of 2.00×104 V.
Answer:
2. [2pt]
Two small, identical spherical conductors carry charges of 6.5 C and -3.6 C. They are separated by a distance of 5.0 cm. Calculate the magnitude of the electrostatic force between these two spheres.
Answer:
3. [2pt]
A capacitor consists of two conductive plates each with an area of 300.0 cm2 separated by a distance of 1.7 mm. If there is a voltage 185.0 V between the plates what will be the charge on each plate?
Answer:
Answer:
Answer:
6. [2pt]
If there is a voltage of 8.5 V between points a and b, what is the current through R1?
Explanation / Answer
1) E = V/D = 2*10^4/0.06 = 3.33*10^5 N/m Answer
2) F = KQ1*Q2/R^2 = 9*(10^9)*6.5*3.6*(10^-12)/(0.05)^2 = 84.24 N Answer
3) C = epsilon_naught*A/D = 8.82*(10^-12)*300*1000/(1.7*10000) = 1.556*10^-10 F
Q = CV = 1.556*(10^-10)*185 = 2.87*10^-8 C Answer
4) Ceq = 8.7*6.8/(8.7+6.8) + 10.8 = 14.617 micro F Answer
5) Req = R1||(R2+R3) = 1.96||(1.75+1.09) = 1.96*2.84/(2.84+1.96) = 1.1596 K Answer
6) I = V/R1 = 8.5/1.96 = 4.336 A Answer
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