1) When the pressure is 1.0 atmosphere, the amount of gas contained in the syrin
ID: 1499032 • Letter: 1
Question
1) When the pressure is 1.0 atmosphere, the amount of gas contained in the syringe is 12.0 cm3. If the syringe plunger is pushed in to the 9.0-cm3mark, the pressure according to Boyle’s law should be:
a) 0.75 atm
b) 1.0 atm
c) 1.25 atm
d) 1.33 atm
2) If the temperature in the room is 20°C, what is the temperature in Kelvin (K)?
a) 68
b) 273
c) 293
d) 300
3) At a temperature of 273 K, the syringe contains 11.0 cm3 of air. How many moles of air are in the syringe?
a) 4.86 X 10-4 moles
b) 0.446 moles
c) 11.0 moles
d) 2.04 X 103 moles
4) The pressure unit of atmospheres can be related to SI units by: 1 atm = 1.013 ´ 105 N/m2. A square meter is a large area. One atmosphere of pressure corresponds to how many N/cm2?
a) 1.013 X 109 N/cm2
b) 1.013 X 107 N/cm2
c) 1.013 X 103 N/cm2
d) 1.013 X 101 N/cm2
Explanation / Answer
1)
pressure, p1=1atm
volume, v1=12cm^3, and volume, v2=9cm^3
use,
P1*V1=P2*V2
1*12=p2*9
===> p2=1.33 atm --->
2)
temperature, T=20 oC
T=20+273
T=293 oK ------->
3)
now,
T3=273 k and V3=11cm^3
P1*V1=P3*V3
1.33*9=P3*11
==> P3=1.09 atm
use,
P*V=n*R*T
p3*v3=n*R*T3
n=p3*v3/R*T3
n=1.09*(1.013*10^5)*11*(10^-2)^3/((8.314)*(273))
n=5.35*10^-4 mole
4)
1atm=1.013*10^5 N/m^3
1atm=1.013*10^5 N/(10^2cm)^2
1atm=1.013*10^1 N/cm^2 -------->
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