Suppose that you have a reflection diffraction grating with n = 125 lines per mi

Question

Suppose that you have a reflection diffraction grating with n = 125 lines per millimeter Light from a sodium lamp passes through the grating and is diffracted onto a distant screen. Two visible lines in the sodium spectrum have wavelengths 498 nm and 569 nm. What is the angular separation deltatheta of the first maxima of these spectral lines generated by this diffraction grating? Express your answer in degrees to two significant figures. How wide does this grating need to be to allow you to resolve the two lines 589.00 and 589.59 nanometers, which are a well known pair of lines for sodium, in the second order (m = 2)? Express your answer in millimeters to two significant figures. Monochromatic light falls on a slit that is 2.10times10^-3 mm wide. If the angle between the first dark fringes on either side of the central maximum is 29.0 degree (dark fringe to dark fringe), what is the wavelength of the light used? Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

lambda/dlambda = m*width*N

589/0.59 = 2* width * 125

widht = 4.0 mm

part 2)

d*sintheta = (m+1/2)*lambda ( for destructiive interference )

m = 0

2*d * sin29 = lambda

lambda = 2.04 x 10^-6 m = 2.04 um

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.