A charged particle is moving in a uniform, constant magnetic field. Which one of

Question

A charged particle is moving in a uniform, constant magnetic field. Which one of the following statements concerning the magnetic force exerted on the particle is false? It does no work on the particle. It increases the speed of the particle. It changes the velocity of the particle. It ran act only on a particle in motion. It does not change the kinetic energy of the particle. A circular current loop with radius of 0.100 m is located in the x-y plane. A magnetic field of strength 2.5 T makes an angle of 60 degree with the i-axis. If loop carries a current of 2.0 A. what is the magnitude of the magnetic force on the loop? Zero N 1.36 N 0.157 N 0.136 N 0.0785 N An electron moves through a region of crossed electric and magnetic fields. The electric field E = 3000 V/m and is directed straight down. The magnetic field B = 0.50 T and is directed to the left. For what velocity v of the electron into the paper will the electric force exactly cancel the magnetic force? 6000 m/s 4500 m/s 3000 m/s A long, straight wire is in the same plane as a nonconducting loop. The wire carries an increasing current/in the direction shown in the figure. There will be a clockwise induced current in the loop. There will be a counterclockwise induced current in the loop. There will be no induced emf and 110 induced current. There will be a clockwise induced emf. but no induced current. There will be a counterclockwise induced emf. but no induced current. An AC generator consists of 6 turns of wire. Each turn has an area of 0.040 m^2 The loop rotates in a uniform magnetic field (B = 0.20 T) at a constant frequency of 50 Hz What is the maximum induccd emf? 0.064 V 2.4 V 2.9 V 15 v 18 V When an RLC series circuit is in resonance, its impedance is: pi/2 Ohm, -pi/2 Ohm a maximum equal to its resistance zero

Explanation / Answer

3(a) It increases the speed of the particle.

Explanation

The magnetic foce acting on the moving charged particle does not increase the speed of the particle. But the direction of the charged partcile gets changed.

We know that speed is scalar and velocity is vector, so the velocity (just the magnitude) remains constant but it now follows a circular path under the inflcuence of magnetic field.

g) option (a) is correct.

Explanation:

Felectric = q E and Fmagnetic = q v B

qE = q v B => v = E/B

v = 3000/0.5 = 6000 m/s

Hence, option (a) is correct.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.