Darcel runs the simulation for the large version of each object. What can he say
ID: 1495080 • Letter: D
Question
Darcel runs the simulation for the large version of each object. What can he say in general about the energies of the objects in the simulation as they roll down the incline? (Select all that apply.)
"The total energy of the system remains constant and is equal to the gravitational potential energy of the object at the top of the incline.""The total kinetic energy of a rolling object is the sum of the rotational kinetic energy about the center of mass and the translational kinetic energy of the center of mass.""The translational kinetic energy is always greater than the rotational kinetic energy.""The potential energy of the system remains constant, and is equal to the total energy."
Explanation / Answer
"The total energy of the system remains constant and is equal to the gravitational potential energy of the object at the top of the incline".Since no velocity at top of the incline and no kE.So, only height of incline matters so, PE=TE.And TE is Constant with conservation of energy principle.
"The total kinetic energy of a rolling object is the sum of the rotational kinetic energy about the center of mass and the translational kinetic energy of the center of mass".Since KE is due to Translational and rotational motion.
"The translational kinetic energy is always greater than the rotational kinetic energy"
May or may not, it depends on value of I( moment of inertia).Yeah, rotational KE will be equal or less than translational KE.
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