A 25kg crate is dragged upward a distance of 40.0m at a constant velocity of 3.0

Question

A 25kg crate is dragged upward a distance of 40.0m at a constant velocity of 3.0m/s by the 350N force of tension by a rope, scraping against the vertical wall as it moves.

A] What is the force exerted by friction?

B] How much work does the force of gravity do over the trip?

C] How much work does tension do over the trip?

D] How much work does the normal force between the crate and the wall do over the trip?

E] How much power output is required to move the crate upward via the rope's 350N of force of tension?

Explanation / Answer

A)    force exerted by friction = (350 N) - (25 * 9.8 N)

                                              = 105 N

B)   work does the force of gravity do over the trip =   - 25 * 9.8 * 40

                                                                                 = - 9800 J

C)    work does tension do over the trip = 350 * 40 = 14000 J

D)    work does the normal force between the crate and the wall do = 0 J

E)    power output is required to move the crate upward = F * v

                                                                                         = 350 * 3   = 1050 W

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