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ID: 1493330 • Letter: 9
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95% Mon Apr 11 2 22 56 AM a E Chrome File Edit View History Bookmarks People Window Help f Facebook Ll C Physics question I Che DIM v3.41 Josh Chapter 10 Simple Har The Angriest Rocket Le Bungie b www.webassign.net 13047794 /web/Student/Assignment-Responses/last?dep App Bookmarks Apple YouTube home Watch Live Sports E O tech Destiny l The BNg faculty.pnc.edu/ptes OTR DestinyTracker De nyLFG.N Eii C. Henry Edwards 9. C+ -1.5 points, CJ10 10. P.05 My Notes Ask Your Teacher A tow truck is pulling a car out of a ditch by means of a steel cable that is 10.5 m long and has a radius of 0.50 cm. When the car just begins to move, the tension in the cable s 840 N. How much has the cable stretched? (See Table 10.1 for appropriate constants) both for Additional Materials Section 10.8 10. -1.5 points, CJ10 10. P.052 My Notes Ask Your Teacher Two stretched cables both experience the same stress The first cable has a radius of 3.45 x 10 m and is subject to a stretching for of 281 N. he radius o the second cab x 10 m. Determine the stretching force acting on the second cable. 4.75 e is N thumbs u Enter a aterials Section 10.8 AA Your work in question (s) 9 will also be submitted or saved. Submit Assignment Save Assignment Progress Practice Another VersionExplanation / Answer
9)
stress = tension /area = 840/(3.142*0.5^2*10^-4) = 1.069*10^7 N/m^2
starin = e/l
for steel wire Young's modulus is Y = 2*10^22 N/m^2
e/l = stress/Y = 1.069*10^7/(2*10^11) = 5.345*10^-5
streched length is e= 5.345*10^-5*10.5 = 0.0005612 m = 0.5612*10^-3 m = 0.5612 mm
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10) Given that stress is same
F1/A1 = F2/A2
F1/(pi*r1^2) = F2/(pi*r2^2)
F1/r1^2 = F2/r2^2
281/(3.45*10^-3)^2 = F2/(4.75*10^-3)^2
F2 = 532.67 N
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