0.6 0.4 S 0.2 0.0 -0.2 0.4 -0.6 0.0 0.10.2 0.30.40.5 Time (ms) 1. Note that the

Question

0.6 0.4 S 0.2 0.0 -0.2 0.4 -0.6 0.0 0.10.2 0.30.40.5 Time (ms) 1. Note that the horizontal scale is in millisecond (ms) units. What is the frequency of the signals? (Include units.) f= 2000 Hz X 2. If the speed of sound is 341 m/s, what is the wavelength of the sound wave? 3. The two signals differ by a phase. What is it? Expressed in degrees: Expressed in radians: 4. If the two microphones were at the same distance from the speaker, the two signals would be in phase: they would lie on top of each other. For the phase difference shown, what is the minimum distance between the two microphones? Dmin

Explanation / Answer

(1)

The time period of the signals is,

T=0.25 ms

frequency is f=1/T =1/(0.25*10^-3) =4000 Hz

(2)

the wavelength is,

lemda =v/f =341/4000 =8.525e-2 m =8.825 cm

(3)

90 degree

pi/2 radians =1.57 radians

(4)

phase diff = (2pi/lemda)* path difference

path diff =lemda/4 =2.13 cm

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