That\'s the second time posting this problem,got it wrong 4 times myself.I\'ll r
ID: 1492124 • Letter: T
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That's the second time posting this problem,got it wrong 4 times myself.I'll rate who ever gets it right,and please double check your work.
***I also posted all the wrong answer i got on the side****
Part D Exercise 21.40 Find the net electric force that the two charges would exert on an electron placed at point on the c-axis at 0.200 m A -3.00 nC point charge is at the origin, and a second -6.50 nC point charge is on the x-axis at 0.800 m Express your answer with the appropriate units. Enter positive value if the force is in the positive r-direction and negative value if the force is in the negative -direction. R: 60-10-19 Submit My Answers Give Up ANSWER 1 F 512.5 N ANSWER 2 F8.2-10-7 N ANSWER 3: F8.2-10-7 N ANSWER 4 F-3.42.10-16 N ANSWER 5 Fa 3.42-10-16 N ANSWER 6 F-3060-10-19 N ANSWER 7: F- 60-10-19 NExplanation / Answer
Electric field at (x =0.200 m ) , E = k q1/r1^2 + kq2/r2^2
= 9*10^9 [ -3*10^-9/0.2^2 - - 6.5*10^-9/0.6^2]
= 9*(-3/0.04 + 6.5/0.36) = -512.5 N/C
Force on electron = Eq = -512.5*(-1.6*10^-19)
= 8.2 *10^-17 N Answer
Be careful with exponential power, which is wrong in previous answers
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