Question 10 of 10 Incorrect X Incorrect Map A sapling learning Consider the foll

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Question 10 of 10 Incorrect X Incorrect Map A sapling learning Consider the following nuclear fusion reaction: H H Each fusion event releases approximately 4.03 Mev of energy. How much total energy, in joules, would be released if all the deuterium atoms in a typical 0.290-kg glass of water were to undergo this fusion reaction? Assume that approximately 0.0135% of all the hydrogen atoms in the water are deuterium. Number 2.52 x 10 A typical human body metabolizes energy from food at a rate of about 92.5 W, on average. How long, in days, would it take a human to metabolize the amount of energy calculated above? Number days 315.23 Incorrect A Previous ® Give Up & View Solution Try Again Next Exit Explanation

Explanation / Answer

a)

no of moles of water, n = m/M

= 290/18

= 16.11 mol

no of Hydrogen atoms = 16.11*6.023*10^23

= 9.7*10^24

no of atoms of deutron atoms, N = 0.0135% of 9.7*10^24

= (0.0135/100)*9.7*10^24

= 1.3*10^21

so, energy released,

E = (N/2)*4.03 Mev

= (1.3*10^21/2)*4.03*10^6*1.6*10^-19 J

= 4.19*10^8 J

b) Power = Energy/time

time taken = Energy/power

= 4.19*10^8/92.5

= 4.53*10^6 s

= 4.53*10^6/(365*24*60*60)

= 0.144 days

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