I have answered part A and Part B. Please do not answer unless you can answer pa

Question

I have answered part A and Part B. Please do not answer unless you can answer part C. A simple pendulum consists of a small object of mass m (the "bob") suspended by a cord of length l of negligible mass. A force F is applied in the horizontal direction (so F =Fi^), moving the bob very slowly so the acceleration is essentially zero. (Note that the magnitude of F will need to vary with the angle that the cord makes with the vertical at any moment.) (Figure 1) Part A Determine the work done by this force, F , to move the pendulum from =0 to =0. Express your answer in terms of the variables m, l, 0, and appropriate constants. Enter the argument of trigonometric function in parenthesis. WF = mgl(1cos(0)) SubmitMy AnswersGive Up Answer Requested Part B Determine the work done by the gravitational force on the bob, FG=mg. Express your answer in terms of the variables m, l, 0, and appropriate constants. WG = mgl(1cos(0)) SubmitMy AnswersGive Up Correct Part C Determine the work done by the force FT that the cord exerts on the bob. Express your answer in terms of the variables m, l, 0, and appropriate constants.

Explanation / Answer

In Part C it is asking us the work done by the tension in the cord. Since the tension in the cord and the instantaneous displacement of the bob are always perpendicular therefore work done by tension force will be zero....

It is true in general also that work done by tension force is always zero. ( Principle of virtual work).

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