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home / study / questions and answers / science / physics / a woman is standing in an elevator holding her ... Question A woman is standing in an elevator holding her 2.3 kg briefcase by its handles.(A)Draw a free-body diagram for the briefcase if the elevator is accelerating downward at 2.50 m/s2 . Draw the force vectors with their tails at the dot. The orientation of your vectors will be graded. The exact length of your vectors will not be graded but the relative length of one to the other will be graded.(B)Calculate the downward pull of the briefcase on the woman’s arm while the elevator is accelerating.

Explanation / Answer

The net acceleration will be: a'=9.8-2.5=7.3 m/s2 (1)

(A) The forces on the briefcase will be 2: own weight (downward),and the normal reaction from woman's arm (upward).

(B) Force on woman's arm (the "new" weight of the briefcase): from (1): ma'=2.3*7.3=16.79 N

OR: mg-N=ma --> N=m(g-a)=16.79 N

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