fari File Edit View History Window Help 004: Sun 2:08:36 AM Yale Univers... Your

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fari File Edit View History Window Help 004: Sun 2:08:36 AM Yale Univers... Your Ta A bar of gold (Au) Is in thermal contact with a bar of silver (Ag) of the same length and area (see figure below). One end of the compound bar is maintained at Ti - 80.5°C, and the opposite end is at T2 -320°C. When the T1-80.5°C, and the opposite end is at T,32.0°C, when the energy transfer reaches steady state what is the temperature at the junction? The thermal | conductivity of gold is 314 W/m·°C, and that of silver is 427 W/m·oc.) 0 Insulation Need Help? alk to Tuter Submit Assignment Save Assignment Progress

Explanation / Answer

(KAdT/l)Gold = (KAdT/l)silver

since Area and length are equal

K1*(80.5- T) = K2*(T - 32)

314*80.2 - 314*T = 427*T - 427*32

25182.8 - 314T = 427T - 13664

25182.8 + 13664 = 427T + 314T

38846.8 = 741 T

T = 38846.8 / 741

T = 52.42 *C

T = 52.4 *C

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