A brick of mass m=0.44kg is set against a spring with a spring constant of k1=52

Question

A brick of mass m=0.44kg is set against a spring with a spring constant of k1=523 N/m which has been compressed by a distance of 0.1 m. Some distance in fron of it, along a frictionless surface, is another spring with a spring constant of k2=493 N/m.

a) How far, d2 in meters, will the second spring compress when the brink runs into it?-----d2=0.013

b)=How fast, v in meters per second, will the brick be moving when it strikes the second spring?---v=3.44

c) Now assume that the surface is rough (not frictionless). You perform the experiment again and observe that the second spring only compresses a distance d2/2. How much energy, in joules, was lost to friction?

NEED HELP SOLVING C

Explanation / Answer

here,

m = 0.44 kg

spring constant , k1 = 523 N/m

spring constant , k2 = 493 N/m

compression in the spring 1 , x1 = 0.1 m

(c)

compression in the seccond spring , x2 = d2/2 = 0.013/2 = 0.0065 m

the energy lost in friction , E = 0.5 * k1*x1^2 - 0.5 * k2*x2^2

E = 0.5 * ( 523 * 0.1^2 - 493 * 0.0065^2)

E = 2.6 J

the energy lost to friction is 2.6 J

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