Suppose that goats have one gene that codes for color, where A is brown and a is

Question

Suppose that goats have one gene that codes for color, where A is brown and a is white. The goats also have another gene that codes for height, where B is tall and b is short. If these two genes are unlinked, what is the probability that a cross between Aa Bb x Aa bb parents will produce three out of five offspring that are brown and short? Enter your answer as a decimal, rather than as a percentage Number 0.0289 Incorrect You may have used the correct formula, but forgot to mutliply by the coefficient. To determine the coefficient, use the binomial expansion or Pascal's triangle.

Explanation / Answer

AaBb Aabb

Gametes- AB, Ab, aB, ab Ab, ab

Cross-

Probability of brown and short offspring = 3/8

Hence, required probability=

= 5C3 (3/8)3(5/8)2

= 10*27*25/32768

= 0.20599

Ab ab AB AABb AaBb Ab AAbb Aabb aB AaBb aaBb ab Aabb aabb

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