3. (15pt) Parallel plates Betn difference of 400V. An electros is released near

Question

3. (15pt) Parallel plates Betn difference of 400V. An electros is released near the lower voltage plate at ero initial velo a. 4pts Sketch the above situatio cen two ventical parallel metal plates 20 em apart in a vacoum,a volumeter measunes s dthe plars ) An electros is released near the bower vollage plate st zero initial velociny eaove situation, b. 3pes Cakulase and skeich E fetween the plases e. 3pes Briefly describe the motion of experiences ignoe gravity d. Spts The electros eventually stri path and calculate and Sahel the forceto electros eventually strikes the ligher voltage pilate. Calcufate its kinetic energy and velocity when i st crie the motion of the electron in the field. Indicate its r

Explanation / Answer

It is very difficult to read the text

The electric field is

E= s/eo = Q/ eo A

In a parallel plate E is uniform therefore V = Ed                                    V potential difference

E= V/d                E= (400-0)/ 0.2     E= 2000 volt/m

Electron is subject to two perpendicular forces, gravity that creates a movement accelerated in the vertical direction and the power that creates a accelerated horizontal movement, the two movements are accelerated, but its fall due to gravity in very small for the mass of electron, but movement must be a parabola with a very slight curvature

W= - mg j = - 9.1 1031 9.8 = 89.18 10-31 N

Fe= - q E i = - 1.6 10-19   2000 = 3.200 10-16 N

We see that the electric force is much greater than the gravitational and consequently acceleration

We calculate the kinetic energy

K= ½ m v2       eje x

since kinematics

. v2 = vo2 + 2 a x              x= 0.2m    vo=0  

Fe= ma    a = Fe /m = -qE/m

. v2 = -2qE x/m

. K = ½ m (-2qE x/m)2 = 2 q2 E2 x2 / m        K = 2 1.62 10-38 20002 0.2 / 3.1 10-31

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