A 3kg block is attached to a massless spring and oscillates back and forth with
ID: 1487861 • Letter: A
Question
A 3kg block is attached to a massless spring and oscillates back and forth with simple harmonic motion according to the equation x(t)=4cos(5t), where x is in meters And t is in seconds. What is the spring constant of the spring? A)43N/m B)12N/m C)75N/m D)20N/m E)60N/m What is the maximum velocity of the block? A)5m/s B)20m/s C)70m/s D)100m/s E)150m/s A 3kg block is attached to a massless spring and oscillates back and forth with simple harmonic motion according to the equation x(t)=4cos(5t), where x is in meters And t is in seconds. What is the spring constant of the spring? A)43N/m B)12N/m C)75N/m D)20N/m E)60N/m What is the maximum velocity of the block? A)5m/s B)20m/s C)70m/s D)100m/s E)150m/s A 3kg block is attached to a massless spring and oscillates back and forth with simple harmonic motion according to the equation x(t)=4cos(5t), where x is in meters And t is in seconds. What is the spring constant of the spring? A)43N/m B)12N/m C)75N/m D)20N/m E)60N/m What is the maximum velocity of the block? A)5m/s B)20m/s C)70m/s D)100m/s E)150m/s What is the spring constant of the spring? A)43N/m B)12N/m C)75N/m D)20N/m E)60N/m What is the maximum velocity of the block? A)5m/s B)20m/s C)70m/s D)100m/s E)150m/sExplanation / Answer
First question:
m=3Kg
x(t)=4*cos(5t)
Comparing with: x(t)=A*cos(wt), then:
Amplitude A=4 m
Angular velocity: w=5 rad/sec
So:
w=sqrt(k/m)
k=m*w^2
k=3*5^2
= 75 N/m (C) is correct
Second question:
Vmax=A*w
=4*5
=20 m/sec (B) is correct
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