The figure shows three point charges. Charge 1 and Charge 2 are on the x-axis, a

Question

The figure shows three point charges. Charge 1 and Charge 2 are on the x-axis, and Charge 3 is one the y axis. The value of the charges are Charge 1 equal to Q, charge 2 equal to 2Q, and Charge 3 equal to q. All the charges are equal distance, d, from the origin (x = y = 0). If Q = 3.5 nC, q = -1.6 nC, and d = 0.12 m, what is the magnitude of the total electric field at the origin, (x = y = 0)? Give your answer to three significant digits in units of N/C. Do not include the units in your answer.

Explanation / Answer

Here ,

as the electric field due to a charge is given as

E= k * q/d^2

Now, the electric field component in x direction is E

Ex = k *2Q/d^2 - k * Q/d^2

Ex = k * Q/d^2

Ex = 9*10^9 * 3.5 *10^-9/.12^2

Ex = 2187.5 N/C

NOw , for the electric field in y direction

Ey = k * q/d^2

Ey = 9*10^9 * 1.6 *10^-9/.12^2

Ey = 1000 N/C

NOw, magnitude of net electric field = sqrt(Ex^2 + Ey^2)

magnitude of net electric field = 2405.3 N/C

the magnitude of net electric field is 2405.3 N/C

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