when the frequency of the sound is (a) 5.0 kHz and (b) 5.0 x 102 Hz. Room Vibrat

Question

when the frequency of the sound is (a) 5.0 kHz and (b) 5.0 x 102 Hz. Room Vibrating air molecule located in the doorway Figure 17.10 Each vibrating molecule of the air in the doorway generates a sound wave that expands outward and bends, or diffracts, around the edges of the doorway. Because of interference effects among the sound waves produced by all the molecules, the sound intensity is mostly confined to the region defined by the angle on either side of the doorway, The high trequencies are bgamed forward inside this coné

Explanation / Answer

a) given, v = 343 m/s

f = 5 kHz = 5000 hz

wavelength of sound wave, lamda = v/f

= 343/5000

= 0.0686 m

we know, condition for distructive interefrence, D*sin(theta) = m*lamda

for minimum angle m = 1

so, sin(theta) = lamda/D

= 0.0686/0.75

theta = sin^-1(0.0686/0.75)

= 5.248 degrees <<<<<<<-----------------Answer

b) f = 500 hz

wavelength of sound wave, lamda = v/f

= 343/500

= 0.686 m

we know, condition for distructive interefrence, D*sin(theta) = m*lamda

for minimum angle m = 1

so, sin(theta) = lamda/D

= 0.686/0.75

theta = sin^-1(0.686/0.75)

= 66.16 degrees <<<<<<<-----------------Answer

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