MULTIPLE CHOICE. Choose the one alternative that best completes the statement or

Question

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Which two temperature changes are equivalent? 1F degree, 1C 1C, 1K 1K, 1F -40C, -40 F A rod has a length 20000m at 20.0 degree C. The length of the rod increases to 2.0005 m when the temperature increases to 40.0 degree C. What is the coefficient of thermal expansion of the material from which the rod is made? 1.25x10^-5/k 5.00x10^-3/K 2.00x10^5/K 5.00x1-^5/K 2.50x10^5/k If 40 kcal of heat is added to 2.0kg of water, what is the resulting temperature change? 60C degree 20 C degree 0.05 Cdegree 40 Cdegree 80 Cdegree What is the power output of a hot air furnace that produces heat at the rate of 160,000 BTU/hr? 80kW 22kW 47kW 1.6 kW 7.6kW 150 kcal of heat raises the temperature of 20 kg of material by 400 degree F. What is the material's specific heat capacity? 150 kcal of heat raises the temperature of 20kg of material by 400 degree F. What is the materials specific heat capacity? 0.75kcal/kg degree C 0.19 kcal/kg degree C 1.31 kcal/kg degree C 1.35 kcal/kg degree C 0.34 kcal/kg degree C 50 g of lead (c=0.11 kcal/kg degree C) at 100 degree C is put into 75 g of water at ) degree C. What is the final temperature of the mixture? 25 degree c 50 degree C 2 degree C 13 degree C 6.8 degree C A camper is about to drink his morning coffee. He pours 400 grams of coffee, initially at 75.0 degree C, into a 250g aluminium cup, initially at 16.0 degree C. What is the equilibrium temperature of the coffee cup system, assuming no heat is lost t the surroundings? The specific heat of aluminium is 900 J (kgK). Assume that the specific heat of coffee is the same as the specific heat of water 65.0 degree C 68.0 Degree C 71.0 degree C 62.0 degree C 45.5 degree C How much heat must be removed from steam to change it to liquid? 540 cal.g 1.8 kcal/g 1 kcal/g 600 cal.g 830 cal/g How much heat is required to change 456 g of ice at -25.0 degree C into water at 25.0 degree C ? The specific heat of ice is 2090 J(kgK) and the latent heat of fusion of water is 33.5x10^4 Jkg. 224kJ 153 kJ 71.5 kJ 72.5 kJ 112 kJ

Explanation / Answer

1) Temperature in Kelvin, TK = TC + 273

=> TK = TC

So, change of 1 oC anf 1 K are equivalent.

2) L = Lo(1 + T)

=> = (L/Lo - 1) / T = (2.0005/2.0000 - 1) / (40 - 20) = 1.25 * 10-5 K-1

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