(8c4p95) A particle P travels with constant speed on a circle of radius r = 6.0

Question

(8c4p95) A particle P travels with constant speed on a circle of radius r = 6.0 m (see the figure) and completes one revolution in 20.0 s. The particle passes through 0 at t = 0. Find the magnitude and direction of each of the following vectors. With respect to 0, find the particle's position vector at t = 5.0 s. What is it magnitude?

What is its angle with repect to the x-axis?

With respect to 0, find the particle's position vector at t = 7.5 s. What is it magnitude?

What is its angle with repect to the x-axis?

With respect to 0, find the particle's position vector at t = 10.0 s. What is it magnitude?

What is its angle with repect to the x-axis?

For the 5.00 s interval from the end of the fifth second to the end of the tenth second, find the magnitude of the particle's displacement.

For the 5.00 s interval from the end of the fifth second to the end of the tenth second, find the particle's average velocity. What is the x-component of the average velocity?

What is the y-component of the average velocity?

Find its velocity at the beginning and end of that 5.00 s interval. What is the x-component of the velocity at t = 5.0 s?

What is the y-component of the velocity at t = 5.0 s?

Find its acceleration at t = 5.0 s? What is the x-component of the acceleration at t = 5.0 s?

What is the y-component of the acceleration at t = 5.0 s?

Find its velocity at the end of that 5.00 s interval. What is the x-component of the velocity at t = 10.0 s?

What is the y-component of the velocity at t = 10.0 s?

Find its acceleration at t = 10.0 s? What is the x-component of the acceleration at t = 10.0 s?

What is the y-component of the acceleration at t = 10.0 s?

Explanation / Answer

Note : Image is not available. I do not know the point O
Assuming it to be (6,0)

In 20 second 360 degree is completed.
In 5 second it will complete [360/20]* 5 = 90 degree

The coordinate of the point is (0m, 6m)

The magnitude or the distance from the origin is

(0^2 + 6^2 ) = 6

The angle is given by tan A = 6 /0 =>
A = 90 degree.

Calculate the rest accordingly

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