15g of steam at 100 degree Celsius is added to 320 g of water at 5 degree Celsiu

Question

15g of steam at 100 degree Celsius is added to 320 g of water at 5 degree Celsius. heat is exchange only between the steam and the water. assume steam condenses. specific heat- water: 4186 J/kg/C Steam: 2010 J/kg/C A) Find final equilibrium temperature of the system B) find total entropy change of water c) find total entropy change of steam for all changes it undergoes D) find entropy change of system. Is the process irreversible? 15g of steam at 100 degree Celsius is added to 320 g of water at 5 degree Celsius. heat is exchange only between the steam and the water. assume steam condenses. specific heat- water: 4186 J/kg/C Steam: 2010 J/kg/C A) Find final equilibrium temperature of the system B) find total entropy change of water c) find total entropy change of steam for all changes it undergoes D) find entropy change of system. Is the process irreversible? 15g of steam at 100 degree Celsius is added to 320 g of water at 5 degree Celsius. heat is exchange only between the steam and the water. assume steam condenses. specific heat- water: 4186 J/kg/C Steam: 2010 J/kg/C A) Find final equilibrium temperature of the system B) find total entropy change of water c) find total entropy change of steam for all changes it undergoes D) find entropy change of system. Is the process irreversible?

Explanation / Answer

A)  using conservation of energy, E = 0

(m_steam) (c_steam)T - (m_water)(c_water)T' = 0

(0.015)(2010)(100- T) - (0.320)(4186)(T - 5) = 0

T 7.09°C

B) total entropy change of water = (m_water)(c_water)T' =(0.320)(4186)(7.09 - 5) =2799.6 J/C

C) total entropy change of steam= (m_steam) (c_steam)T = (0.015)(2010)(100- 7.09) =2801.2 J/C

D)  entropy change of system = 2799.6 + 2801.2 =5600.8 J/C

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